2[k-(4k+12)+10]=2(k+2)

Solution for 2[k-(4k+12)+10]=2(k+2) equation:

Simplifying
2[k + -1(4k + 12) + 10] = 2(k + 2)

Reorder the terms:
2[k + -1(12 + 4k) + 10] = 2(k + 2)
2[k + (12 * -1 + 4k * -1) + 10] = 2(k + 2)
2[k + (-12 + -4k) + 10] = 2(k + 2)

Reorder the terms:
2[-12 + 10 + k + -4k] = 2(k + 2)

Combine like terms: -12 + 10 = -2
2[-2 + k + -4k] = 2(k + 2)

Combine like terms: k + -4k = -3k
2[-2 + -3k] = 2(k + 2)
[-2 * 2 + -3k * 2] = 2(k + 2)
[-4 + -6k] = 2(k + 2)

Reorder the terms:
-4 + -6k = 2(2 + k)
-4 + -6k = (2 * 2 + k * 2)
-4 + -6k = (4 + 2k)

Solving
-4 + -6k = 4 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
-4 + -6k + -2k = 4 + 2k + -2k

Combine like terms: -6k + -2k = -8k
-4 + -8k = 4 + 2k + -2k

Combine like terms: 2k + -2k = 0
-4 + -8k = 4 + 0
-4 + -8k = 4

Add '4' to each side of the equation.
-4 + 4 + -8k = 4 + 4

Combine like terms: -4 + 4 = 0
0 + -8k = 4 + 4
-8k = 4 + 4

Combine like terms: 4 + 4 = 8
-8k = 8

Divide each side by '-8'.
k = -1

Simplifying
k = -1